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2ef19ad79a
Not all locales on linux are UTF-8, the most notable being the C locale. Python will use the ASCII codec for stream IO in this case and will barf on the Copyright sign at the top of .g4a files. Bugzilla: https://bugs.gentoo.org/show_bug.cgi?id=519434 Signed-off-by: Rémi Cardona <remi@gentoo.org> Signed-off-by: Damien Lespiau <damien.lespiau@intel.com>
127 lines
3.8 KiB
Python
Executable File
127 lines
3.8 KiB
Python
Executable File
#!/usr/bin/env python3
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# Copyright © 2011 Intel Corporation
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#
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# Permission is hereby granted, free of charge, to any person obtaining a copy
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# of this software and associated documentation files (the "Software"), to deal
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# in the Software without restriction, including without limitation the rights
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# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
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# copies of the Software, and to permit persons to whom the Software is
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# furnished to do so, subject to the following conditions:
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#
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# The above copyright notice and this permission notice (including the next
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# paragraph) shall be included in all copies or substantial portions of the
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# Software.
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#
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# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
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# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
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# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
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# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
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# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
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# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
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# SOFTWARE.
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#
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# Authors:
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# Ben Widawsky <ben@bwidawsk.net>
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#very limited C-like preprocessor
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#limitations:
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# no macro substitutions
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# no multiline definitions
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# divide operator is //
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import sys,re
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# make sure both input file and stdout are handled as utf-8 text, regardless
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# of current locale (eg. LANG=C which tells python to use ascii encoding)
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sys.stdout = open(sys.__stdout__.fileno(), "a", encoding="utf-8")
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file = open(sys.argv[1], "r", encoding="utf-8")
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lines = file.readlines()
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len(lines)
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out = dict()
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defines = dict()
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count = 0
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#create a dict for our output
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for line in lines:
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out[count] = line
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count = count + 1
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#done is considered #define <name> <number>
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def is_done(string):
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m = re.match("#define\s+(\w+?)\s+([a-fA-F0-9\-]+?)\s*$", string)
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return m
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#skip macros, the real cpp will handle it
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def skip(string):
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#macro
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m = re.match("#define\s+\w+\(.+", string)
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return m != None
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#put contants which are done being evaluated into the dictionary
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def easy_constants():
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ret = 0
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for lineno, string in out.items():
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if skip(string):
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continue
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m = is_done(string)
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if m != None:
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key = m.group(1)
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value = m.group(2)
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if not key in defines:
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defines[key] = int(eval(value))
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ret = 1
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return ret
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#replace names with dictionary values
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def simple_replace():
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ret = 0
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for lineno, string in out.items():
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if skip(string):
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continue
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for key, value in defines.items():
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if is_done(string):
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continue
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s = re.subn(key, repr(value), string)
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if s[1] > 0:
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out[lineno] = s[0]
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ret = s[1]
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return ret
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#evaluate expressions to try to simplify them
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def collapse_constants():
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ret = 0
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for lineno, string in out.items():
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if skip(string):
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continue
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if is_done(string):
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continue
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m = re.match("#define\s+(.+?)\s+(.+)$", string)
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if m != None:
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try:
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out[lineno] = "#define " + m.group(1) + " " + repr(eval(m.group(2)))
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ret = 1
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except NameError as ne:
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#this happens before a variable is resolved in simple_replace
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continue
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except SyntaxError:
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#this happens with something like #define foo bar, which the
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#regular cpp can handle
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continue
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except:
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raise KeyboardInterrupt
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return ret;
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while True:
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ret = 0
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ret += easy_constants()
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ret += simple_replace()
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ret += collapse_constants()
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if ret == 0:
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break;
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for lineno, string in out.items():
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print(string.rstrip())
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