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Create 10_2_integer2lehex.sh

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Shannon Appelcline 2020-10-20 13:09:43 -10:00 committed by GitHub
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commit b59e0d2f5e
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#!/bin/bash
if [ -z $1 ];
then
echo "You must include an integer as an argument.";
exit;
fi
if (( $1 > "2147483647" )) || (( $1 < "-2147483647" ));
then
echo "Your number ($1) must be between -2147483647 and 2147483647";
exit;
fi
if [ $1 -lt 0 ];
then
integer=$(echo $((-$1)));
negative=1;
else
integer=$1;
negative=0;
fi
hex=$(printf '%08x\n' $integer | sed 's/^\(00\)*//');
hexfirst=$(echo $hex | cut -c1)
[[ 0x$hexfirst -gt 0x7 ]] && hex="00"$hex
lehex=$(echo $hex | tac -rs .. | echo "$(tr -d '\n')");
if [ "$negative" -eq "1" ];
then
lehex=$(printf '%x\n' $((0x$lehex | 0x80)))
fi
size=$(echo -n $lehex | wc -c | awk '{print $1/2}');
hexcodeprefix=$(printf '%02x\n' $size);
echo "Integer: $1";
echo "LE Hex: $lehex";
echo "Length: $size bytes";
echo "Hexcode: $hexcodeprefix$lehex";